自定义哈希不要抛出异常

自定义哈希不要抛出异常

白云母晶簇

C.89: Make a hash noexcept

C.89:保证哈希不会抛出异常

Reason(原因)

Users of hashed containers use hash indirectly and don't expect simple access to throw. It's a standard-library requirement.

哈希容器的用户间接地使用哈希功能,不会希望简单的操作发生异常。这是标准库的要求。

Example, bad(反面示例)

<code>template<>struct hash { // thoroughly bad hash specialization  using result_type = size_t;  using argument_type = My_type;  size_t operator() (const My_type & x) const  {    size_t xs = x.s.size();    if (xs < 4) throw Bad_My_type{};  // "Nobody expects the Spanish inquisition!"    return hash<size>()(x.s.size()) ^ trim(x.s);  }};int main(){  unordered_map m;  My_type mt{ "asdfg" };  m[mt] = 7;  cout << m[My_type{ "asdfg" }] << '\\n';}/<size>/<code>

If you have to define a hash specialization, try simply to let it combine standard-library hash specializations with ^ (xor). That tends to work better than "cleverness" for non-specialists.

如果你已经定义了哈希特化,争取简单地实现为通过异或和标准库哈希特化的组合。

Enforcement(实现建议)

  • Flag throwing hashes.
  • 提示抛出异常的哈希。

原文链接

https://github.com/isocpp/CppCoreGuidelines/blob/master/CppCoreGuidelines.md#c89-make-a-hash-noexcept


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